Which of the following equations represents a line that is parallel to the line 1 point with the equation below?*
y = -3x +4

A. 6x+2y=15
B. 3x-y=7
C. 2x-3y=6
D. X+3y=1

Step-by-step explanation:

step 1. I assume the question is which of the following equations is parallel to y = -3x + 4

step 2. parallel equation have identical slopes (m)

step 3. 6x + 2y = 15 or y = -3x + 15/2 (solve for y)

step 4. 3x - y = 7 or y = 3x - 7 (solve for y)

step 5. 2x - 3y = 6 or y = (2/3)x - 2 (solve for y)

step 6. x + 3y = 1 or y = (-1/3)x + 1/3

step 7. since y = mx + b we want m to be the same

step 8. the answer is A since they both have the same slope.

1,645,493,059.35

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3