A simple random sample of 140 residents in a certain town was polled the week after the Super Bowl. 75 of them reported that they watched the game on TV. a) Construct the 95% CI for the proportion of people that watched Super Bowl. b) The prognosis stated that the proportion of people watching the game is 48.1%. Does this prognosis contradict your findings

a) The 95% CI for the proportion of people that watched Super Bowl is (0.4531, 0.6183).

b) 48.1% = 0.481 is part of the confidence interval, which means that this prognosis does not contradict the findings.

Step-by-step explanation:

a) Construct the 95% CI for the proportion of people that watched Super Bowl.

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

75 out of 140 watched the Super Bowl:

This means that

95% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 95% CI for the proportion of people that watched Super Bowl is (0.4531, 0.6183).

b) The prognosis stated that the proportion of people watching the game is 48.1%. Does this prognosis contradict your findings

48.1% = 0.481 is part of the confidence interval, which means that this prognosis does not contradict the findings.

hi,

you half the rectangle that you ae asking about so then you would see the scale factor of 1/2 the one u have selected, the one on top is half.

hope this !