In Δ PQR, PQ = 17.4 m and PR = 7.6 m. K lies on QR such that ∠ PKQ = 137 °. find (i) ∠ QPR (ii) the length of QK
using the trigonometric ratios

here:given

PQ=17.4m

PR=7.6m

QR=?

NOW:QR^2=PQ^2-PR^2

QR=[(17.4)^2-(7.6)^2]^1/2

QR=[302.76-57.76]^1/2

QR=15.65

now: in tringle PKR

ANGLE PKR=43 DEGREE            [180-137] IN TRINGLE ALL SIDES SUM 180]

tan(43)=PR/KR

Tan(43)=7.6/KR

KR=7.6/0.932

KR=8.15

NOW:QK=QR-KR

QK=15.65-8.15

QK=7.5

{3 + i, 3 - i, 3, -1}

step-by-step explanation: