We want to find the zeros of this polynomial:
p(x) = (2x^2 – 9x + 7)(x - 2)

p(x) = (2x² - 9x + 7)(x - 2)

2x² - 9x + 7 = 0 or x - 2 = 0

x = 2

a = 2, b = -9, c = 7

Delta = (-9)² - 4 * 2 * 7 = 81 - 56 = 25

x = (-(-9) - 5)/(2 * 2) = 4/4 = 1

x = (-(-9) + 5)/(2 * 2) = 14/4 = 3,75

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.