Solve the following quadratic equation using the quadratic formula.

−2y^2+5=7y

y=(7±√89)/-4

Step-by-step explanation:

y=(-b±√b^2 -4ac)/2a

Rewrite given equation in quadratic form so it is -2y-7y+5=0

Then, in formula, sub -2 for a, -7 for b, and 5 for c

y=-(-7)±√(-7)^2 -4(-2)(5)/2(-2)

When you multiply that out you get

7±√49-(-40)/-4

The next step is the answer given above

If you need the answer not in sq rt form, it is y=-4.1085 and y=0.0608

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

its an acute right triangle

step-by-step explanation: