Please help ASAP!! Ms. Clandestine is planning to take her study group on a field trip to an amusement park. The regular cost is $25 per person. There is a party special that costs $15 per person with an additional $150 fee for a private room where students can eat lunch. Ms. Clandestine is trying to decide if she should use the regular price or the party special.

Question 1
Write an equation to show the total cost of the regular price with x people.

Y=5x+2
Y=2x+5
Y=25x
None of the above

Question 2
Write an equation to show the total cost of the party special with x people.

Y=15x+25
Y=15x+150
Y=150x+15
None of the above

Question 3
Solve your system of equations making sure to SHOW ALL YOUR WORK. You can use any of the methods we discussed in class (Graphing, Substitution, or Elimination)

Question 4
What is the solution to this system?

(-375,15)
(-15,375)
(375,15)
(15,375)

Question 5
What does the solution mean in relation to THIS PROBLEM?

Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck! cutt.ly/XzW3SUN

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.