Find the equation of the parabola whose vertex is the origin and whose directrix is x = -4

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1) if V(0;0) and x= -4, then common view of the required equiation is:

(y-k)²=4p(x-h), where focus is in (h-p;k), the vertex is in (h;k), the directrix is x=h+p, p<0 and y=k is simmetry axis;

2) if the V(0;0), then h=k=0 and the required equiation is:

y²=4px;

3) if the directrix equation is x=h+p, where h=0, then p= -4 (according to the condition the directrix equation is x= -4), then the required equation is:

y²= -16x

y²= -16x

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step-by-step explanation:

at least i think its

associative property hopes this ! : )

step-by-step explanation: