A seagull is flying 20 feet above sea level while a shark is swimming 30 feet below sea level. What is the distance between the seagull and the shark?

50 ft

Step-by-step explanation:

The seagull is 20 ft above sea level.

Shark is 30 ft below seas level.

To find their distance, add their distances from sea level because it is middle ground between where they both are:

= 20 + 30

= 50 ft

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

can you put the picture up?

step-by-step explanation: