If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(4)] 2.

If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)] 2

the answer is b.)

< 1=< 2

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.