Mathematics, 10.03.2021 18:40 12345678822
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The points plotted below are on the graph of a polynomial. How many roots
of the polynomial lie between x = -4 and x = 3?
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Mathematics, 21.06.2019 13:30
Rose drew a regression line for this paired data set. her line passed through (1,â2) and (3,â5) . what is the equation of rose's regression line?
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Mathematics, 21.06.2019 19:00
Find the equation of the line with slope =8 and passing through (6,53) write your equation in the form y=mx+b
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Mathematics, 21.06.2019 20:00
A. what does the point (4, 122) represent? b. what is the unit rate? c. what is the cost of buying 10 tickets?
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Mathematics, 21.06.2019 21:30
In δabc shown below, â bac is congruent to â bca: triangle abc, where angles a and c are congruent given: base â bac and â acb are congruent. prove: δabc is an isosceles triangle. when completed (fill in the blanks), the following paragraph proves that line segment ab is congruent to line segment bc making δabc an isosceles triangle. (4 points) construct a perpendicular bisector from point b to line segment ac . label the point of intersection between this perpendicular bisector and line segment ac as point d: mâ bda and mâ bdc is 90° by the definition of a perpendicular bisector. â bda is congruent to â bdc by the definition of congruent angles. line segment ad is congruent to line segment dc by by the definition of a perpendicular bisector. δbad is congruent to δbcd by the line segment ab is congruent to line segment bc because consequently, δabc is isosceles by definition of an isosceles triangle. 1. corresponding parts of congruent triangles are congruent (cpctc) 2. the definition of a perpendicular bisector 1. the definition of a perpendicular bisector 2. the definition of congruent angles 1. the definition of congruent angles 2. the definition of a perpendicular bisector 1. angle-side-angle (asa) postulate 2. corresponding parts of congruent triangles are congruent (cpctc)
Answers: 1
PLS HELP FAST WILL GIVE BRAINIEST
The points plotted below are on the graph of a polynomial. How ma...
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