A dragonfish is swimming at -900 m relative to sea level. It rises 250 m. What is the dragonfish´s new depth relative to sea level? Show your work.

1150 m

Step-by-step explanation:

Given that,

A dragonfish is swimming at -900 m relative to sea level.

It rises 250 m.

We need to find the dragonfish´s new depth relative to sea level. Let the new position is x. So,

x = 250-(-900)

= 250+900

= 1150 m

Hence, the new position is 1150 m.

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