Suppose a white dwarf star has a diameter of approximately 1.8083 to the power of 4 km. Use the formula 4n to the power of 2 to find the approximate surface area of the star.

The surface area of the star is 3.2700 x square kilometres.

EXPLANATIONS:

Diameter of the star = 1.8083 x Km.

Surface area of the star = 4

Where n is the radius of the star.

So that;

n =

   = 0.90415 x

n =  0.90415 x Km

Thus,

Surface area = 4 x

                     = 326994889

Surface area = 3.2700 x

Therefore, the surface area of the star is 3.2700 x square kilometres.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

b. hoped i'm right lol

step-by-step explanation: