A company can send a maximum of 40 workers to complete a task. The manager needs to limit the total cost of the workers
within $1000. He needs to pay $30 and $20 to each female
and male worker for this task respectively. Write a system of
inequalities to express this situation. What is the least possible
number of male workers the manager should send to meet the
requirements?
male workers

20

Step-by-step explanation:

For the sake of the problem, let's make female workers "x" and male workers "y".

x+y<40       This equation shows that the total number of workers has a max of 40.

30x+20y<1,000      This equation shows that the total cost the manager pays ($30 to each woman, $20 to each man) has a max of $1,000.  

Now you can solve for x and y.

X+y<40

-y       -y

X<-y+40

Substitute -y+40 in for X in the second equation

30(-y+40)+20y<1,000      

-30y+1200+20y<1,000         Distribute

-10y+1,200<1,000      Combine like terms

-10y<-200                   Subtract 1,200

y>20                Divide by -10; flip the sign

Since y>20, and y=male workers, you now know that the minimum

number of male workers he should send is 20

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64