Please help, i'll give brainliest and a lot of points :) Triangle ABC has vertices A(2,3), B(4,5), and C(6,1).

If ΔABC is dilated by a scale factor of 3/2
and has the origin as the center of dilation, what are the coordinates of B'?

A) B' (9, 3/2)
B) B' (5 1/2, 6 1/2)
C) B' (6, 15/2)
D) B' (3, 4.5)

I can't answer your question but get an idea of this

Step-by-step explanation:

If ΔABC is dilated by a scale factor of 1/2

with a dilation center of A, what will be the coordinates of point C'?

Point C is at (2,0)

Cut each coordinate in half to get (1,0)

2*(1/2) = 1

0*(1/2) = 0

So point C will move to (1,0)

Not the answer but an example on how to do it

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier