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Mathematics, 09.03.2021 18:10 bobby1415

The work of a student to solve a set of equations is shown: Equation 1: m = 8 + 2n
Equation 2: 6m = 4 + 4n

Step 1: βˆ’6(m) = βˆ’6(8 + 2n) [Equation 1 is multiplied by βˆ’6.]
6m = 4 + 4n [Equation 2]
Step 2: βˆ’6m = βˆ’48 βˆ’ 12n [Equation 1 in Step 1 is simplified.]
6m = 4 + 4n [Equation 2]
Step 3: βˆ’6m + 6m = βˆ’48 βˆ’ 12n + 4n [Equations in Step 2 are added.]
Step 4: 0 = βˆ’48 βˆ’ 8n
Step 5: n = βˆ’6

In which step did the student first make an error?
Step 3
Step 5
Step 4
Step 2

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Answers: 3

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The work of a student to solve a set of equations is shown: Equation 1: m = 8 + 2n
Equation 2...
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