Mathematics, 09.03.2021 18:10 bobby1415
The work of a student to solve a set of equations is shown:
Equation 1: m = 8 + 2n
Equation 2: 6m = 4 + 4n
Step 1: β6(m) = β6(8 + 2n) [Equation 1 is multiplied by β6.]
6m = 4 + 4n [Equation 2]
Step 2: β6m = β48 β 12n [Equation 1 in Step 1 is simplified.]
6m = 4 + 4n [Equation 2]
Step 3: β6m + 6m = β48 β 12n + 4n [Equations in Step 2 are added.]
Step 4: 0 = β48 β 8n
Step 5: n = β6
In which step did the student first make an error?
Step 3
Step 5
Step 4
Step 2
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The work of a student to solve a set of equations is shown:
Equation 1: m = 8 + 2n
Equation 2...
Equation 2...
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