The Celluloid Cinema sold 150 tickets to a movie. Some of these were child tickets and the rest were adult tickets. A child ticket cost $7 and an adult ticket is cost $10. If the cinema sold $1470 worth of tickets, which system of equations could be used to determine how
many adult tickets, a, and how many child tickets, c, were sold?

a + c = 150

7.75a + 10.25b = 1470

Step-by-step explanation:

Let a represent the number of adult tickets that were sold.

Let c represent the number of child tickets that were sold.

The celluloid cinema sold 150 tickets to a movie. Some of these were child tickets and the rest were adult tickets. This means that

a + c = 150 - - - - - - - - - - - - - -1

A child ticket cost $7.75 and an adult ticket cost $10.25. If the cinema sold $1470 worth of tickets, it means that

7.75a + 10.25b = 1470 - - - - - - - - -2

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )