A rock is thrown upward from the top of a 112-foot high cliff overlooking the ocean at a speed of 96 feet per second. The rock's helght above ocean can be modeled by the equation H(t) = - 16t ^ 2 + 96t + 112 . What is the maximum height in feet, that the rock will reach? Do not include units in your answer

256 feet

Step-by-step explanation:

To find the maximum height, we have to find the vertex of the parabola, which is formed by the situation.

First, find the axis of symmetry using -(b/2a). This will give us the x value of the vertex.

Plug in b into the equation:

-(b/2a)

-(96 / 2(-16))

-(96 / -32)

-(-3)

= 3

Now, plug in 3 as x into the given equation, to find the maximum height that the rock will reach:

H(t) = -16t² + 96t + 112

H(3) = -16(3²) + 96(3) + 112

H(3) = 256

So, the maximum height that the rock will reach is 256 feet

false

step-by-step explanation:

whenever we assume a point on a plane then according to geometry it will definitely have 2 dimensions and if it assumed in space then it will have 3 dimensions.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)