I really need yall help with all of these problems please and thank you if you can answer this qiuckly

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°

1875cm³

step-by-step explanation:

we have a 20 × 20 × 5 container with (what im guessing is a) 5 × 5 × 5 hole in the center. first, we need to calculate the volume of the 20 × 20 × 5 container.

20 × 20 × 5 = 2000cm³

now, we need to calculate the volume of the hole.

5 × 5 × 5 = 125cm³

now to find the area of the container, we take to solid area of the container, and subtract the area of the hole.

2000cm³ - 125cm³ = 1875cm³

given expression is

we have radical  

we need to select an option that has same radical

(a)  

this expression has cube root instead of square root . so it is not a like radical.

(b)

y is included inside the radical. so it is not a like radical.

(c)

this expression has cube root instead of square root . so it is not a like radical.

(d)

5 is inside the radical square root. so it is   a like radical.