The student body President of a high school claims to know the names of at least 1000 of the 1800 students at the school. To test this claim, the Student Government Advisor randomly selects 100 students from the school and asks the President to name each one. The President is able to correctly name 46 of the students. What would be the 99% confidence interval for p in this case?

The 99% confidence interval for p in this case is (0.3317, 0.5883).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

Randomly selects 100 students from the school and asks the President to name each one. The President is able to correctly name 46 of the students.

This means that:

99% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for p in this case is (0.3317, 0.5883).

javeir earned 56 dollors more than kyle so kyle and javier had 14w but javier made 56 dollors more so 14w plus 56 equals 70w so kyle has 14w

step-by-step explanation: hope i plz give me brainliest with the points so this is not constant cause it says last week so its clearly not every week

i dont get the question

step-by-step explanation: