A new cookie cake company is offering a special deal: order one cookie cake at the
regular price, and get a second cookie cake
with a diameter twice the length of the first for
the same price. Desmond orders a cookie cake
with an 8-inch diameter. What is the area of the
second cookie cake Desmond receives?
Usen 3.14.
F 50.24 in?
G 100,48 in.2
H 200.96 in?
J 804 in.
2

200.96in^2

Step-by-step explanation:

If the 1st cookie cake is 8" for its diameter and the 2nd cookie cake will have twice the length diameter of the 1st cookie cake .You will do 2 × 8 to get the diameter of the 2nd cookie cake.

First cookie cake diameter is 8".

Second cookie cake's diameter is 16".

Since we need the radius to find the area of the 2nd cookie cake we're going to do 16 / 2 which equals 8 so 8 is the radius.

A=(pi)r^2

A=(pi)8^2 *to the 2nd power means times by the same number

A=(pi)64

A= (3.14)(64)

A=200.96

=200.96^2

pi= 3.14 *for this problem

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v