Pls help, it might be easy A bag contains 22 blue marbles, 22 red marbles, and 22 yellow marbles,
If Jenna randomly draws a marble from the bag (and puts it back) 1515 times, how many times should she expect to pull a yellow marble?

There are 28 red (R) marbles and 22 blue(B) marbles.

Case 1: Probability of picking a red marble

Favorable cases for picking a red marbles = 28

Exhaustive cases for picking the red marble = 50

So, the Probability = 28/50 = 0.56

Case 2: Probability of picking a blue marble

Favorable cases for picking a blue marbles = 22

Exhaustive cases for picking the red marble = 50

So, the Probability = 22/50 = 0.44

Case 3: Probability of picking a red marble after a blue marble is picked first

Favorable cases for picking the blue ball first = event A = 22

Exhaustive cases = 50 cases

So, P(A) = 22/50 = 11/25 = 0.44

Favorable cases for picking a red marbles = event B = 26

Exhaustive cases for picking the red marble = 49 since a blue marble has been picked.

So, the P(B) = 26/49 = 0.53

So, P(AxB) = P(A)P(B/A) = 22/50 * 26/49 = 0.44*0.53= 0.2332

I have the same answer ^^^

The answer maybbe c