Let R be the region bounded by the following curves. Use the method of your choice to find the volume of the solid generated when R is revolved about the​ x-axis. y = 6x^2 & y = 28 - x^2

V = 7168π /3  

Step-by-step explanation:

R ( region ) bounded by curves ; y = 6x^2 , y = 28 - x^2

determine the volume of the solid generated when R is revolved about the x-axis

 Volume = 7168π /3    

attached below is the remaining part of the detailed solution to the problem above

Given that :

y = 6x^2----- ( 1 )   ,  y = 28 - x^2 ------ ( 2 )

equate  ( 1 ) and ( 2 )

6x^2 = 28 - x^2

7x^2 = 28

∴ x = √4 = ± 2

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.

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step-by-step explanation:

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