Solve the equation by completing the square. 0=x^2-14x+46 A. B. C. D.

x = 16

Step-by-step explanation:

0=x^2-14x+46 is to be solved for x by completing the square.  The first two terms, x^2 and -14x, are the incomplete square.  We must find a term to add to, and then subtract from x^2 - 14x, so that we have a perfects square on the left and a negative number on the right:

x^2 - 14x = x^2 - 14x + (half of -14)^2 - (half of -14)^2 results in transformation of the original 0=x^2-14x+46 to

x^2 - 14x + 49 - 49 + 46 = 0, which simplifies to:

(x - 7)^2 - 3 = 0.  We want to solve this for x.

To do that, rewrite (x - 7)^2 - 3 = 0 as (x - 7)^2 = 3, and then square both sides.  We get:

x - 7 = 9, or x = 16

x1=7-(square)3 x2=7+(square)3

Step-by-step explanation:

Swipe the sides of equation

Solve the quadratic equation ax^2+bx+c=0

Then using: x=((-)b+-(square)b^2-4ac):2a

Separate the solutions

Simplify

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

the terms of a geometric sequence can be found by beginning with the first term and multiplying by the common ratio repeatedly. a recursive formula for a geometric sequence with common ratio r is given by an=ran−1 a n = r a n − 1 for n≥2 n ≥ 2 .

step-by-step explanation: