Translate f(x) = |x| so that it's translated up by 5 units and vertically stretched by a factor of 3. What's the new function g(x)?
A) g(x) = |3x|+ 5
B) g(x) = 3|x|+-5
C) g(x) = 3|xl + 5
D) g(x) = |3x| +-5

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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