At which values of x does the function F(x) have a vertical asymptote? Check all that apply.
f(x)=7/2x(x+3)(x-9)

x=0, x= - 3, x=9

Step-by-step explanation:

f(x)=7/2x(x+3)(x-9)

f(x) doesn't exist for x=0,-3,9

as

vertical asymptote:

x=0, x= - 3, x=9

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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the answer is b