If ∆ABC≅∆DEF, and AB=15, BC=20, and FE=3x-7, then x=?

x= 29

Step-by-step explanation:

Since, ∆ABC is congruent to ∆DEF,

AB= DE(i)

BC= EF(ii)

AC= DF(iii)

From (ii), BC= EF,

So, 3x-7 = 20

3x= 20+7= 27

x= 27/3 = 9

Hope it helps you

rounding to the nearest thousandth would be 452,000

the answer will be