If the length of the segment AB is 5, and BC is 9, and CD is three, find the difference between the furthest and shortest possible distance of AD? A: 12
B: 13
C: 14
D: 15
E: 16

9514 1404 393

  E.  16

Step-by-step explanation:

If the order of points on the line is ABCD, the distance between A and D is ...

  AB +BC +CD = 5 + 9 + 3 = 17

If the order of points on the line is BADC, the distance between A and D is ...

  BC -BA -DC = 9 -5 -3 = 1

Then the difference between the longest and shortest possible distances AD is ...

  17 - 1 = 16 . . . . matches choice E

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.

i’m here for points.