Find the equation of the line that passes throughP(6,0) andQ(1,−1).

Step-by-step explanation:

y=mx+b where m is the slope and b is the y intercept

m=(y2-y1)/(x2-x1), we have points (6,0) and (1,-1)

m=(-1-0)/(1-6)=1/5 so we have

y=x/5+b, using point (6,0) we can solve for b

0=6/5+b

b=-6/5

y=x/5-6/5 or more neatly

y=(x-6)/5

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation: