Shelby leaves her house at 9:00am on her bike at a speed of 320 meters per minute. At 10:30 am, her brother, Colby leaves the house on his bike and tries to catch up with Shelby. Colby rides at a speed of 500 meters per minute. At what time will Colby catch up with Shelby?

Step-by-step explanation:

320t=500(t-1.5)

320t=500t-750

-180t=-750

t=25/6

t=4+1/6 hours

So Colby catches up 4 1/6 hours after Shelby left. Since she left at 9am

9+4hours + 10 minutes. So they have travelled the same distance at 1:10pm

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

42.4

step-by-step explanation:

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