5 numbers :
mode = n median= n+1 mean = n+2 Range = n+3

find 2 sets of numbers

3,3,4,6,6

4,4,5,6,7

5,5,6,6,8

Step-by-step explanation:

mode = n

median= n+1

mean = n+2

Range = n+3

let sets:

a,b,c,d,e

mode = n, at least two of them are the same and equal to n

n,n,c,d,e

median belong to the set, in ascending order:

n,n,n+1,d,e

which means d,e ≥ n+1, d≠e

mean is n+2

5(n+2)=n+n+n+1+d+e

2n+9=d+e

Assume e is the maximum:

Range is n+3:

e-n=n+3

e=2n+3

d=6≥n+1

n≤5,

Set is n,n,n+1,6,n+3

n+1≤6≤n+3

3≤n≤5

3,3,4,6,6 bimodal

4,4,5,6,7

5,5,6,6,8 bimodal

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.

i think the answer would be c