A 14 ​-pound mixture of coffee that contains both decaffeinated and regular coffee costs ​$37. The decaffeinated coffee costs ​$2 per​ pound, and the regular coffee costs ​$3 per pound.

The number of pounds of:

Decaffeinated coffee = x = 5 pounds

Regular coffee = y = 9 pounds

Step-by-step explanation:

A 14 ​-pound mixture of coffee that contains both decaffeinated and regular coffee costs ​$37. The decaffeinated coffee costs ​$2 per​ pound, and the regular coffee costs ​$3 per pound.

Let the number of pounds of:

Decaffeinated coffee = x

Regular coffee = y

Hence, our system of equations =

x + y = 14 Equation

x = 14 - y

2x + 3y = 37 Equation 2

We substitute 14 - y for x in Equation 2

= 2(14 - y) + 3y = 37

= 28 - 2y + 3y = 37

= - 2y + 3y = 37 - 28

= y = 9 pounds

Solving for x

x = 14 - y

x = 14 - 9

x = 5 pounds

Therefore,

The number of pounds of:

Decaffeinated coffee = x = 5 pounds

Regular coffee = y = 9 pounds

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.