Mathematics, 06.03.2021 03:50 cathydaves

Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct? Jesse
100x^2−100=(10x)^2−10^2
=(10x-10)(10x+10)
=10(x-1)(10)(x+1)
=100(x-1)(x+1)

Benjamin
100x^2-100=100(x^2-1)
=100(x-1)(x+1)

Answers: 3

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Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct? Jesse 100x^2−100=(10x)^2−10^2 =(10x-10)(10x+10) =10(x-1)(10)(x+1) =100(x-1)(x+1) Benjamin 100x^2-100=100(x^2-1) =100(x-1)(x+1)

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Another question on Mathematics

Jesse and Benjamin are asked to factor 100x^2−100. Here are their solutions. Who is correct? Jesse
100x^2−100=(10x)^2−10^2
=(10x-10)(10x+10)
=10(x-1)(10)(x+1)
=100(x-1)(x+1)

Benjamin
100x^2-100=100(x^2-1)
=100(x-1)(x+1)