You and your friend are selling tickets to a charity event. You sell two adult tickets and six student tickets for $12. Your friend sells for adult tickets and 15 student tickets for $27. What is the cost of each ticket?

Your friend sells "for"adult tickets and 15 student tickets for $27, I think you meant "four" adult tickets and 15 student tickets for $27.

Adult ticket costs $3

Student ticket cost $1

Step-by-step explanation:

Let the cost adult ticket be represented as X

And cost student tickets be represented as y

Such that two adult tickets and six student tickets for $12 would be expressed as

2x+6y=12

And

four adult tickets and 15 student tickets for $27.

4x+15y=27

The equations to solve becomes

2x+6y=12equation 1

4x+15y=27equation2

Solving

Multiply equation 1by 4 and equation 2by 2

8x+24y=48---equation 3

8x+30y=54equation4

Subtracting equation 3from equation 4

6y=6

Y=6/6

Y=1

Putting the value of y=1in equation 1and solving for x becomes

2x+6y=12

2x+6x1=12

2x=12-6

2x=6

X=6/2=3

Adult ticket costs $3

Student ticket cost $1

the answer is d on edge

step-by-step explanation: