Write all three forms (slope intercept, point slope and standard) of a line containing the points (4, -11/3) and (1/2, -29/6).

See explanations below

Step-by-step explanation:

Slope intercept form of the equation is expressed as y = mx+b

m is the slope

b is the intercept

Given the coordinates (4, -11/3) and (1/2, -29/6)

Slope m = -29/6-(-11/3)÷(1/2-4)

m = (-29/6+11/3)÷(-7/2)

m = -29+22/6÷(-7/2)

m = -7/6÷(-7/2)

m = -7/6×2/-7

m = 2/6

m = 1/3

Get the intercept b

Substitute m= 1/3 and (4, -11/3) into y = MX+b

-11/3 = 1/3(4)+b

-11/3 = 4/3+b

b= -11/3-4/3

b= -15/3

b =-5

Get the required equation

y = 1/3 x -5 (slope-intercept form)

Point slope form of the equation is expressed as y-y0 = m(x-x0)

Substituting m = 1/3 and the point (4,-11/3)

x0 = 4

y0 = -11/3

y - (-11/3) = 1/3(x-4)

y+11/3 = 1/3(x-4) (point-slope form)

For standard format

Recall that y = 1/3x - 5

Multiply through by 3

3y = 1/3x(3)-5(3)

3y = x-15

3y-x = -15(standard form)

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: