A single 6 side die is 'rolled twice. There are 36 equally likely outcomes. Find the probability of getting two numbers whose sum is
8.The probability of getting two numbers whose sum is 8 is

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).

Therefore, the number of possible outcomes when two dice are thrown is 36.

Now, the possible outcomes of getting a sum equal to 8 is {(2,6),(3,5),(4,4),(5,3),(6,2)}, which means the number of favourable outcome is 5.

Therefore, probability P of getting a sum equal to 8 is:

P= 36/5

Hence, the probability of getting a sum equal to 8 is 36/5 .

Step-by-step explanation:

Hope it is helpful...

step-by-step explanation: