I need help with these three equations
3x - 2 = x + 10
X+4=19-2x
8z - 20 =z +15

1st answer is 6, 2nd is 5, 3rd is 5

Step-by-step explanation:

3x-2=x+10

3x-x=10+2

2x=12

x=12÷2

x=6

x+4=19-2x

x+2x=19-4

3x=15

x=15÷3

x=5

8z-20=z+15

8z-z=15+20

7z=35

z=35÷7

z=5

plzz mark me as brainliest

3x-2=x+10

x=6

x+4=19-2x

x=5

8z-20=z+15

z=5

Step-by-step explanation:

3x-2=x+10

+2 on both sides

3x-2(+2)=x+10(+2)  =>  3x=x+12

subtract x on both sides

3x(-x)=x(-x)+12   =>  2x=12

divide 2 on both sides

2x/2=12/2

= x=6

x+4=19-2x

subtract 4 on both sides

x+4(-4)=19(-4)-2x    =>    x=15-2x

add 2x on both sides    

x(+2x)=15-2x(+2x)     =>    3x=15

divide 3 on both sides

3x/3=15/3

= x=5

8z-20=z+15

subtract z on both sides

8z(-z)-20=z(-z)+15    =>  7z-20=15

add 20 on both sides

7z-20(+20)=15(+20)

7z=35

divide 7 on both sides

7z/7=35/7

= z=5

4th option is correct xy=-10

if this was to u plzz mark me the brainliest

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4