Diagonals AC and BD form right angles at point M in parallelogram ABCD. Prove ABCD is a rhombus. Parallelogram A B C D is shown. Diagonals are drawn from point A to point C and from point B to point D and intersect at point M. Sides A B and D C are parallel and sides B C and A D are parallel. A square is drawn around point M.

Statements

Reasons
1. ABCD is a parallelogram 1. given
2. ∠AMB, ∠BMC, ∠CMD, and ∠DMA are right angles 2. given
3. ∠AMB ≅ ∠BMC ≅ ∠CMD ≅ ∠DMA 3. right angles are congruent
4. AC bisects BD;
BD bisects AC; 4. diagonals of a parallelogram bisect each other
5. AM ≅ MC, MB ≅ MD 5. definition of a bisector
6. ? 6. SAS congruency theorem
7. AB ≅ BC ≅ CD ≅ DA 7. CPCTC
8. figure ABCD is a rhombus 8. definition of a rhombus
△ABC ≅ △ADC ≅ △BAD ≅ △BCD
△AMB ≅ △CMB ≅ △CMD ≅ △AMD
△ABC ≅ △ADC ≅ △AMD ≅ △BMC
△AMB ≅ △CMD ≅ △BAD ≅ △BCD

yes

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

answer: its the third option.

step-by-step explanation:

i just took the test.

1.3 million hoops i believe