PLZ HELPP Which system of equations has exactly one solution?

O 2x-4y=8
x+y= 7

O 3x+y=-1
6x+2y =-2

O 3x+3y = 3
-6x-6y = 3

O 3x-2y = 4
-3x+2y = 4

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step-by-step explanation:

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116