A ball is thrown from an initial height of 6 feet with an initial upward velocity of 17 ft/s. The ball's height h (in feet) after t seconds is given by the following. h=6+17t-16t^2

Find all values of t for which the ball's height is 10 feet.

Round your answer(s) to the nearest hundredth.
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t=___seconds

32

Explanation:

6 + 29t - 16t^2 = 18. 16t^2 - 29t + 12 = 0. t = (29 +- √(29^2 - 4*12*16))/32.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.