If
are the roots of 3x²+2x-1=0 then 1/
+1/
is​

2

Step-by-step explanation:

Given the quadratic equation

3x²+2x-1=0

Let tthe root be α and β

Sum of root α+β = -b/a

Product of root αβ = c/a

Given that;

a = 3, b = 2 and c = -1

α+β = -2/3

αβ = -1/3

To get 1/α + 1/β

Find the LCM

1/α + 1/β

= (α+β)/αβ

= (-2/3)/(-1/3)

= -2/3 * 3/-1

=  2

Hence the required answer  is 2

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752