Suppose that in a certain country, 10% of the elderly people have diabetes (call this Event D). It is also known that 30% of the elderly people are living below poverty level (call this Event P), 35% of the elderly population falls into at least one of these categories, and 5% of the elderly population falls into both of these categories. If a randomly selected elderly person is living below the poverty level, what is the probability that she/he has diabetes

0.1667 = 16.67% probability that she/he has diabetes

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Living below the poverty level.

Event B: Having diabetes.

30% of the elderly people are living below poverty level.

This means that

5% of the elderly population falls into both of these categories.

This means that

If a randomly selected elderly person is living below the poverty level, what is the probability that she/he has diabetes

0.1667 = 16.67% probability that she/he has diabetes

step-by-step explanation:

rectangles are made up of 4 right angles, which means that a side and a base meet perpendicular to one another.   their slopes then have to reflect perpendicular slopes.   perpendicular slopes are opposite reciprocals of one another.   for example, if the slope of one line is +2/3, then the perpendicular slope to that would be -3/2.   so we look for that combination in our choices.

all of them satisfy that condition (so what's the question, i guess? )