Mathematics, 05.03.2021 01:00 haleyrene2663

Prove: An odd times an odd equals an odd.
(2m + 1)(2n + 1) = [ ? ]mn + [ ]m+ [ ]n + [ ]
= 2([ ]mn + m + 1) +1
= odd

Answers: 3

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Prove: An odd times an odd equals an odd.
(2m + 1)(2n + 1) = [ ? ]mn + [ ]m+ [ ]n + [ ]
...

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Prove: An odd times an odd equals an odd. (2m + 1)(2n + 1) = [ ? ]mn + [ ]m+ [ ]n + [ ] = 2([ ]mn + m + 1) +1 = odd

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Another question on Mathematics

Prove: An odd times an odd equals an odd.
(2m + 1)(2n + 1) = [ ? ]mn + [ ]m+ [ ]n + [ ]
= 2([ ]mn + m + 1) +1
= odd