Quadrilateral abcd is rotated 90 degrees clockwise about the origin. What are the coordinates of A'B'C'D?

Option B is correct.

The coordinate of A' is (-2 , -1)

Explanation:

The coordinates of ABCD are A = (-1,2) , B(1,1) , C =(1,-1) and D(-2,-2).

Rotation means moving the shape  around a fixed point clockwise or anticlockwise, and by a certain number of degrees.

Rule for 90° counterclockwise rotation about the origin:

or we can say that switch x and y in the coordinates and make y value opposite.

Then, the coordinate of A' :

Therefore, the coordinate of A' in the quadrilateral A'B'C'D' is, (-2 ,-1)

your answer is A

Step-by-step explanation:

have a nice day!! ^_^

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

you have to put the graph on here with the question

step-by-step explanation: