A 1,300 kg car moving at 20 m/s and a 900 kg car moving at 15 m/a in precisely opposite directions crash head on. If we consider this event to be a perfectly inelastic collision, what is the speed of the cars after the impact?

17.96m/s

Step-by-step explanation:

Based on law of conservation of momentum;

m1u1 +m2u2 =(m1+m2)v

v is the velocities of the car after impact

Substitute the given values

1300(20)+900(15) = (1300+900)v

26000 + 13500 = 2200v

39500 = 2200v

v = 39500/2200

v = 17.96m/s

Hence the speed of the cars after impact is 17.96m/s

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step-by-step explanation:

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