The distance y (in miles) that Train A travels in x hours is represented by the equation y=68x . The graph shows the distance that Train B travels. (0, 0) and (1, 64).

For train A, the distance traveled as a function of time in hours is written as:

y = 68*x

For train B, we know that it's equation passes through the points (0, 0) and (1, 64)

Remember that:

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

Then the slope for the equation of train B is:

a = (64 - 0)/(1 - 0) = 64

Then equation of train B is something like:

y = 64*x + b

Now, we know that it passes through the point (0, 0), this means that when x = 0, we also have y = 0, then if we replace these two values in the equation we get:

0 = 64*0 + b

0 = 0 +b

then b = 0

This means that the equation for train B is:

y = 64*x

Where again, y is the distance in miles and x is the time in hours.

If we look at both equations, we can see that train A has a larger slope, which means that for each unit of time, train A travels a larger distance, then we can conclude that train A is faster than train B.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!