z = 6/2 + oi
Mathematics, 04.03.2021 17:00 weeblordd
What is the rectangular form of z= 6 (cos(3pi/3) + i sin(3pi/4))
z = -6/2 + oi
z = 6/2 + oi
z = -3sqrt2 +3sqrt2
z= 3sqrt2 + 3sqrt2
Here is the answer.
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What is the rectangular form of z= 6 (cos(3pi/3) + i sin(3pi/4))
z = -6/2 + oi
z = 6/2 + oi
z = 6/2 + oi
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