Will mark brainliest and rate 5/5 Suppose a plane intersects a cube through three intersecting edges
How can you ensure that the triangle cross section is an equilateral triangle?
1. The corner of the cube can be sliced off such that the three verticies of the triangle are at the same distance from the corner of the cube
2. The corner of the cube can be sliced off such that the plane intersects the base
3. The corner of the cube can be sliced off such that the plane is perpendicular to the base

you need to give us more information since we can't answer

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.