Dan buys a car for £2,200 it depreciates at a rate of 0.5% per year how much would it be worth in 6 years ​

Given:

The initial value of car = £2,200

Depreciation rate = 0.5%

To find:

The worth of car after 6 years.

Solution:

Exponential decay model:

Where, a is the initial value, r is the rate of depreciation and t is number of years.

Putting a=2200, r=0.005 and t=6, we get

Therefore, the worth of the car after 6 years is £2134.82.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.