3. Mason, standing just outside his apartment building, throws a baseball upward from an initial height of 5 feet above ground level at an initial velocity of 90 ft/sec. The height of the baseball in terms of elapsed time is a quadratic relationship. The generalized equation is f(x) = –16x2 + v0x + h0, where v0 represents initial velocity and h0 represents initial height. Bill, on his third floor balcony 40 feet above ground level, launches his drone helicopter that ascends at a constant rate of 25 ft/sec. If Mason throws the baseball at the same time that Bill begins the ascent flight with his helicopter, formulate a system of equations to determine at what elapsed time(s) and height(s) the baseball would possibly strike the helicopter.

answer: the 4 kilogram bag

step-by-step explanation: this is because if you divide the number of kilograms into the total it will tell you how much each individual kilogram would be worth. 2 kilos is 7 and change 3 would be around 6 ish and the 4 kilo would be 4.6 and change and the 5 kilos would be like 4.88

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step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.