In ARST, r = 52 cm, s = 55 cm and ZT=48°. Find the length of t, to the nearest
centimeter.

9514 1404 393

  44 cm

Step-by-step explanation:

The law of cosines is applicable.

  t^2 = r^2 + s^2 -2rs·cos(T)

  t^2 = 52^2 +55^2 -2·52·55·cos(48°) ≈ 1901.57

  t ≈ √1901.57 ≈ 43.607

The length of t is about 44 cm.

Hey there!

By the law of cosines,

t² = (52)² + (55)² - 2 × 52 × 55 × cos(48°)

t² ≈ 1901.57

t² = √1901.57

t² = 43.607

Therefore;

i would have to say it is c.

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>